stupid_idiot
Group: Members
Posts: 344
Joined: Oct. 2006 |
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Posted: Dec. 07 2007,12:41 |
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Big Fat Warning:
Hi all,
None of the methods described here actually work.
I haven't found any workable solution yet.
Everything I've posted are just preliminary attempts.
Please do not use ANY of these examples in their unmodified form on any source code!!!
Problems:
-- No reliable way to preserve directives ("#define", "#ifdef", "#endif", etc).
-- "Missing semicolon" compilation errors after deleting comment blocks (the comment blocks were acting the role of semicolons by signifying the end of a function).
-- Most probably, there are many, many more problems which I haven't ran into yet.
I am a newbie who is very new to sed and regular expressions, and:
I am not even sure sed is the proper tool for this purpose (stripping source code).
I am also a total Perl newbie (only just started reading the 'Llama Book' AKA 'Learning Perl, Third Edition' from O'Reilly).
(I wholeheartedly recommend the 'Llama Book' to anyone who is new to Perl -- It is very well written!)
Speaking as a total Perl newbie:
IMHO, I think someone who is versed in Perl may be able to produce a more ideal solution in Perl.
| Code Sample | find ./ -name "*.h" | \
while read i; do \
cpp -P -fpreprocessed "$i" > "$i.tmp" \
&& mv "$i.tmp" "$i"; done
find ./ -name "*.h" | \
while read i; do \
sed -i '/^ *$/d' "$i"; done |
This will recursively strip all comments and empty lines from any C headers in the current directory. This would help reduce the size of any '-dev' extensions.
Any improvements are most welcome!
Thanks.
Explanation:| Code Sample | | cpp -P -fpreprocessed "$i" > "$i.tmp" && mv "$i.tmp" "$i"; done |
1. Process all '.h' files with 'cpp' and overwrite original files with processed files.| Code Sample | | sed -i '/^ *$/d' "$i" |
2. '/^ *$/d' -- Remove lines that: begin with any number of spaces and end after any number of spaces (i.e. lines that contain only spaces).
Possibly useful also:
1. 'whitespace_stripper.sh'| Code Sample | for i in "$@";
do sed -i '/^ *$/d' "$i"; done |
e.g. 'whitespace_stripper.sh file1 file2 file3 file4 [...]'
2. 'stripsh' (strip shell scripts)| Code Sample | for i in "$@";
do sed -i -e 's/\t*#.*//g' \
-e 's/\ *#.*//g' \
-e '/^#/d' \
-e '/^\t*#/d' \
-e '/^ *#/d' \
-e '/^ *$/d' \
"$i"; done |
e.g. 'stripsh file1 file2 file3 file4 [...]'
NOTE: This script has a problem -- It deletes the first line of any script; for example:You have to put the line back again after running the script.
Question for everyone: How do we make 'sed' ignore lines that begin with "#!"?
Thank you very much!
Explanation of above script:
's/\t*#.*//g' -- (Substitution) Pattern: Begins with any number of TABs ("\t"), followed by a "#", followed by any number of any character (".*"). Replacement: Null (i.e. deletes the relevant part of matching lines -- does NOT mean deleting the entire line).
'/^\t*#/d' -- (Deletion) Delete lines that: begin with any number of TABs, followed by a "#" (i.e. bash and perl comments).
'/^ *#/d' -- (Deletion) Delete lines that: begin with any number of SPACEs, followed by a "#" (i.e. bash and perl comments).
'/^ *$/d' -- (Deletion) Delete lines that: begin with any number of SPACEs, followed by an end-of-line ("$") -- i.e. delete empty lines.
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